document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91310>Question 91310</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 cm more than 5 times its width.  If the area of the rectangle is 89 cm2, find the dimensions of the rectangle to the nearest thousandth.\r<BR>\n" );
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document.write( "I wonder if this is somewhat on track? I have been baffled for the past three hours,on this equation. <BR>\n" );
document.write( "(1+2x)(5+2x)=89<BR>\n" );
document.write( "3+-the square root of 93/2<BR>\n" );
document.write( "the square root of 93 divided by 2=9.64divided by 2=4.862182 plus three=7.82182<BR>\n" );
document.write( "and 4.862182-3=1.82182 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66319 by </B><A HREF=/tutors/aboutme.mpl?userid=tutor_paul><B>tutor_paul(519)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutor_paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutor_paul><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write an equation for the length in terms of width:<BR>\n" );
document.write( "Equation #1: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=5W%2B1 ALIGN=MIDDLE  ALT=\"L=5W%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Write an expression for the Area:<BR>\n" );
document.write( "Equation #2: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=LW=89 ALIGN=MIDDLE  ALT=\"LW=89\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now you have 2 equations with 2 unknowns. Any time you have at lease as many equations as you have unknowns, you can find the unknowns!<BR>\n" );
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document.write( "Substitute the value of L from Equation #1 into Equation #2:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285W%2B1%29W=89 ALIGN=MIDDLE  ALT=\"%285W%2B1%29W=89\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5W%5E2%2BW-89=0 ALIGN=MIDDLE  ALT=\"5W%5E2%2BW-89=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Apply the quadratic formula:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=%28-1%2B-sqrt%281%5E2-%284%2A5%2A%28-89%29%29%29%29%2F%282%2A5%29 ALIGN=MIDDLE  ALT=\"W=%28-1%2B-sqrt%281%5E2-%284%2A5%2A%28-89%29%29%29%29%2F%282%2A5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=%28-1%2B-sqrt%281781%29%29%2F10 ALIGN=MIDDLE  ALT=\"W=%28-1%2B-sqrt%281781%29%29%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "W=(-1+-42.2)/10<BR>\n" );
document.write( "W=4.12,W=-4.32<BR>\n" );
document.write( "The width needs to be positive, so throw out the negative result:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28W=4.12%29 ALIGN=MIDDLE  ALT=\"highlight%28W=4.12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now, substitute this value of W into Equation #1 to find L.<BR>\n" );
document.write( "I will leave that part to you :-)<BR>\n" );
document.write( "Goos Luck,<BR>\n" );
document.write( "tutor_paul@yahoo.com\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );