document.write( "Question 91336: I am so bad with these can someone help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "x = log7(1/49)\r
\n" ); document.write( "\n" ); document.write( "The 7 is slightly below the log not beside it. I hope that helps.
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Algebra.Com's Answer #66310 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
x = log7(1/49)
\n" ); document.write( "==============
\n" ); document.write( "Think of a logarithm in terms of what it means in exponent form.
\n" ); document.write( "The \"7\" is the base, the \"1/49\" is the answer, and the logarithm is the exponent. In other words, you problem can be re-written as:
\n" ); document.write( "\"7%5Ex=1%2F49\"
\n" ); document.write( "When written in this form, you can easily see that
\n" ); document.write( "\"highlight%28x=-2%29\"
\n" ); document.write( "That is your answer.
\n" ); document.write( "Good luck,
\n" ); document.write( "tutor_paul@yahoo.com\r
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