document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047513>Question 1047513</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that the area of an equilateral triangle is 78 cm22, find its perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #663066 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=663066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=ewatrrr&illustration_name=EquilateralTriangleArea.jpg\">.<BR>\n" );
document.write( "A = (1/2)bh<BR>\n" );
document.write( "A = (1/4)s^2&#8730;3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284%2A78%2Fsqrt%283%29%29+=+s ALIGN=MIDDLE  ALT=\"sqrt%284%2A78%2Fsqrt%283%29%29+=+s\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "P = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3sqrt%284%2A78%2Fsqrt%283%29%29 ALIGN=MIDDLE  ALT=\"3sqrt%284%2A78%2Fsqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );