document.write( "Question 1047445: A passenger train traveled 100 miles in the same amount of time it took a fright train to travel 80 miles. The rate of the freight was 5 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train \n" ); document.write( "

Algebra.Com's Answer #663051 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "A passenger train traveled 100 miles in the same amount of time it took a fright train to travel 80 miles. The rate of the freight was 5 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train
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Let rate of passenger train be S
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document.write( "Then rate of freight train is: S - 5
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document.write( "We then get the following TIME equation: 
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document.write( "100(S - 5) = 80S ------ Cross-multiplying
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document.write( "100S - 500 = 80S
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document.write( "100S - 80S = 500
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document.write( "20S = 500
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document.write( "S, or rate of passenger train was: , or  \n" );
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