document.write( "Question 1047445: A passenger train traveled 100 miles in the same amount of time it took a fright train to travel 80 miles. The rate of the freight was 5 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train \n" ); document.write( "

Algebra.Com's Answer #663049 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+t+\"$ = time in hrs for both trains
\n" ); document.write( "Let $\"+s+\"$ = speed of the passenger train in mi/hr
\n" ); document.write( " $\"+s+-+5+\"$ = speed of the freight train in mi/hr
\n" ); document.write( "---------------------
\n" ); document.write( "Equation for passenger train:
\n" ); document.write( "(1) $\"+100+=+s%2At+\"$
\n" ); document.write( "Equation for freight train:
\n" ); document.write( "(2) $\"+80+=+%28+s+-+5+%29%2At+\"$
\n" ); document.write( "------------------------
\n" ); document.write( "(1) $\"+t+=+100%2Fs+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+80+=+%28+s-5+%29%2A%28+100%2Fs+%29+\"$
\n" ); document.write( "(2) $\"+80s+=+100s+-+500+\"$
\n" ); document.write( "(2) $\"+20s+=+500+\"$
\n" ); document.write( "(2) $\"+s+=+25+\"$ mi/hr
\n" ); document.write( "and
\n" ); document.write( " $\"+s+-+5+=+20+\"$
\n" ); document.write( "The rate of the passenger train is 25 mi/hr
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+100+=+s%2At+\"$
\n" ); document.write( "(1) $\"+100+=+25%2At+\"$
\n" ); document.write( "(1) $\"+t+=+4+\"$ hrs
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+80+=+%28+s+-+5+%29%2At+\"$
\n" ); document.write( "(2) $\"+80+=+%28+25+-+5+%29%2At+\"$
\n" ); document.write( "(2) $\"+80+=+20t+\"$
\n" ); document.write( "(2) $\"+t+=+4+\"$ hrs
\n" ); document.write( "OK \n" ); document.write( "

\n" );