document.write( "Question 1047511: The sum of three consecutive odd integers is .11 more than twice the second one. Find all three consecutive integers. Show your work. \n" ); document.write( "

Algebra.Com's Answer #663042 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "The sum of three consecutive odd integers is .11 more than twice the second one. Find all three consecutive integers. Show your work.
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Let first integer be F
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document.write( "Then others are: F + 2, and F + 4
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document.write( "We then get: F + F + 2 + F + 4 = 2(F + 2) + 11
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document.write( "3F + 6 = 2F + 4 + 11
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document.write( "3F - 2F = 15 - 6
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document.write( "F, or 1st integer = 
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document.write( "2nd: 9 + 2
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document.write( "3rd: 9 + 4
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document.write( "It's very EASY.....far from being complex! \n" );
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