document.write( "Question 1047491: The length of a rectangle is
\n" ); document.write( "1 ft
\n" ); document.write( " more than twice the width, and the area of the rectangle is
\n" ); document.write( "28 ft2
\n" ); document.write( ". Find the dimensions of the rectangle.
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Algebra.Com's Answer #663024 by Boreal(15235)\"\" \"About 
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W=x
\n" ); document.write( "L=2x+1
\n" ); document.write( "Area=(2x+1)x=28
\n" ); document.write( "2x^2+x=28
\n" ); document.write( "2x^2+x-28=0
\n" ); document.write( "(2x-7)(x+4)=0
\n" ); document.write( "x=3.5,-4. Only 3.5 makes sense.
\n" ); document.write( "2x+1=8
\n" ); document.write( "That area is 28 ft^2
\n" ); document.write( "width is 3.5 feet and length is 8 feet.
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