document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047485>Question 1047485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When the Celsius temperature is 0 degrees, the corresponding Fahrenheit temperature is 32 degrees. When the Celsius temperature is 100 degrees, the corresponding Fahrenheit temperature is 212 degrees. Let C represent the Celsius temperature and F the Fahrenheit temperature. \r<BR>\n" );
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document.write( "A) Express F as an exact linear function of C.\r<BR>\n" );
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document.write( "B) Solve the equation in part (a) for C, thus expressing C as a function of F.\r<BR>\n" );
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document.write( "c) For what temperature if F=C a true statement? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662985 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=(9/5)C+32<BR>\n" );
document.write( "F-32=(9/5)C<BR>\n" );
document.write( "(5/9)(F-32)=C<BR>\n" );
document.write( "When C=F<BR>\n" );
document.write( "C=(5/9)(C-32)<BR>\n" );
document.write( "but C=(9/9)C<BR>\n" );
document.write( "Therefor (9/9)C=(5/9)(C-32)=(5/9)C-(160/9)<BR>\n" );
document.write( "moving the (5/9)C over, (4/9)C=-(160/9)<BR>\n" );
document.write( "multiply both sides by 9<BR>\n" );
document.write( "4C=-160<BR>\n" );
document.write( "C=-40<BR>\n" );
document.write( "F=C at -40 degrees.\r<BR>\n" );
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