document.write( "Question 1047482: Larry Mitchell invested part of his $30000 advance at 3% annual interest and the rest at 6%anual simple interest .if his total yearly interest from both account is $930 find the amount invested in each rate \n" ); document.write( "

Algebra.Com's Answer #662981 by ewatrrr(24785) $\"\"$ $\"About$

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.06x + .03(30000 - x) = 930
\n" ); document.write( "x = 30/.03 = $1000, amount at 6% \n" ); document.write( "

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