document.write( "Question 1047410: Hi, I have a word problem I need help with.
\n" ); document.write( "Four friends have different numbers of cows on their farms. Jorge has 3 times as many cows as Carla. Marcus has half as many cows as Jorge. Dominick has 2 less than 4 times as many cows as Carla. How many cows does each person have if they have a total of 169 cows?\r
\n" ); document.write( "\n" ); document.write( "I'm having a problem with the equations of Marcus and Dominik.And I'm not sure how to write the equations of either of them. But isn't Carla \"X\", and Jorge \" 3X\"?
\n" ); document.write( "Thank you. \n" ); document.write( "

Algebra.Com's Answer #662941 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "Hi, I have a word problem I need help with.
\n" ); document.write( "Four friends have different numbers of cows on their farms. Jorge has 3 times as many cows as Carla. Marcus has half as many cows as Jorge. Dominick has 2 less than 4 times as many cows as Carla. How many cows does each person have if they have a total of 169 cows?\r
\n" ); document.write( "\n" ); document.write( "I'm having a problem with the equations of Marcus and Dominik.And I'm not sure how to write the equations of either of them. But isn't Carla \"X\", and Jorge \" 3X\"?
\n" ); document.write( "Thank you.
\n" ); document.write( "

Yes, if Carla's number is X, then Jorge's is: 3X\r
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document.write( "Anyway, let's do it my way!
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document.write( "Let number of cows Carla has be C
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document.write( "Then Jorge has 3C
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document.write( "Marcus' count: 
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document.write( "Dominick's count: 4C - 2
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document.write( "Since the sum is 169, then we get: 
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document.write( "16C + 3C = 342 ------- Multiplying by LCD, 2
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document.write( "19C = 342 
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document.write( "C, or Carla has:  
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document.write( "Jorge has: 3(18)
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document.write( "Marcus has: 
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document.write( "Dominick has: 4(18) - 2
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document.write( "I'm sure you're able to calculate the last 3.
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document.write( "See how easy that was? It's not COMPLEX at all. \n" );
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