document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047401>Question 1047401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify<BR>\n" );
document.write( "1/squareroot of 3+2  +  1/square root of 3-2<BR>\n" );
document.write( "This is from surds. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662907 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The common denominator is 1/(3-4)=-1. That is the product of the two denominators, which have no internal products, only the first term squared + the second term squared.<BR>\n" );
document.write( "Then the first term in the numerator is sqrt(3)-2, for that is the result of dividing sqrt(3)+2 into the common denominator of sqrt(3)+2*sqrt(3)-2.<BR>\n" );
document.write( "The numerator is sqrt(3)-2+ sqrt(3)+2<BR>\n" );
document.write( "This is 2 sqrt(3)<BR>\n" );
document.write( "The answer is -2 sqrt(3) </SPAN>\n" );
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