document.write( "Question 1047318: A 1/2\" diameter brass rod is used in producing 500 slotted screws 1 5/8\" in length, 1/2\" diameter, with 1/8\" allowance for cutting off and finishing each screw. Determine weight of rod.\r
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document.write( "Brass weighs .311 lbs. per cu. in.\r
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document.write( "My attempt:\r
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document.write( "500 * .5 * 1.63 * .13 = 52.975 = 53 in.\r
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document.write( "The rod is cylindrical. Volume: pi * r^2 * length (or height).\r
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document.write( "3.1416 * .25 * .25 * 53 = 10.40 cu. in.\r
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document.write( "10.40 * .311 = 3.23 lbs.\r
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document.write( "Where am I correct ? \n" );
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Algebra.Com's Answer #662849 by addingup(3677)![]() ![]() You can put this solution on YOUR website! The way I read it: \n" ); document.write( "each screw is 1 5/8\" long + 1/8\" for finishing, so in raw form the bar stock for each screw is 1 5/8+1/8 = 1 6/8 = 1 3/4 = 1.75 \n" ); document.write( "And we have 500 screws: \n" ); document.write( "500*1.75 = 875 inches long. \n" ); document.write( "Diameter: 1/2 = radius 1/4 or 0.25 \n" ); document.write( "Volume: Pi*0.25^2*875 = 171.81 in^3 \n" ); document.write( "Weight: \n" ); document.write( "171.81*.311 = 53.43 lbs is the weight of the rod \n" ); document.write( ": \n" ); document.write( "John \n" ); document.write( " |