document.write( "Question 1047286: How do I find the solution to this equation by completing the square:\r
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Algebra.Com's Answer #662842 by MathTherapy(10555)\"\" \"About 
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How do I find the solution to this equation by completing the square:\r
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\"2x%5E2+-+5x+=+7\"
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document.write( "\"2x%5E2%2F2+-+%285%2F2%29x+=+%287%2F2%29\" ------- DIVIDING each side by 2 to make the LEADING coefficient, 1
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document.write( "\"x%5E2+-+%285%2F2%29x+=+7%2F2\"
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document.write( "\"x%5E2+-+%285%2F2%29x+%2B+%28-+5%2F4%29%5E2+=+7%2F2+%2B+%28-+5%2F4%29%5E2\" ------ Taking , SQUARING it, and ADDING this result to EACH SIDE
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document.write( "\"%28x+-+5%2F4%29%5E2+=+7%2F2+%2B+25%2F16\"
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document.write( "\"%28x+-+5%2F4%29%5E2+=+56%2F16+%2B+25%2F16\" ------ Changing \"7%2F2\" to denominator, 16
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document.write( "\"%28x+-+5%2F4%29%5E2+=+81%2F16\"
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document.write( "\"sqrt%28%28x+-+5%2F4%29%29%5E2+=+%22+%22%2B-+sqrt%2881%2F16%29\" ------- Taking square root of both sides
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document.write( "\"x+-+5%2F4+=+%22+%22%2B-+9%2F4\"
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document.write( "\"x+=+5%2F4+%2B-+9%2F4\"
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