document.write( "Question 1047236: 75% of high school students have seen at least one episode of news. Last month, a random sample of 120 high school students were selected and asked if they had seen at least one episode of news. Out of the 120, 85 of them said they had seen at least one episode. Is there enough evidence to claim the population proportion of all high school student that have watched at least one episode is less than 75% at the 0.05 level of significance?
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document.write( "a. Are the requirements met to run a test like this?
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document.write( "b. What are the hypotheses for this test?
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document.write( "c. Compute the test statistic and the p-value for this test.
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document.write( "d. What is your conclusion at the 0.05 level of significance
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Algebra.Com's Answer #662748 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "a. Are the requirements met to run a test like this? n > 30 \n" ); document.write( "b. What are the hypotheses for this test? \n" ); document.write( "c. Compute the test statistic and the p-value for this test. \n" ); document.write( "d. What is your conclusion at the 0.02 level of significance \n" ); document.write( "H0: p = .75 \n" ); document.write( "H1: p < .75 claim \n" ); document.write( "sample proportion = p-hat = 85/120 = 0.71 \n" ); document.write( "test stat:: z(0.71) = \n" ); document.write( "p-value = .1558 \n" ); document.write( ".1558 > .05 \n" ); document.write( "evidence does not support claim the population proportion of all high school students \n" ); document.write( " that have watched at least one episode is less than 75% at the 0.05 level of significance. \n" ); document.write( " \n" ); document.write( " |