document.write( "Question 1047181: carmines boat has a top speed of 9 mph in still water. while traveling on a river at TopSpeed she went 10 miles upstream in the same amount of time she went 20 miles downstream. Find the rate of the river current. \n" ); document.write( "
Algebra.Com's Answer #662690 by josmiceli(19441)\"\" \"About 
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Let \"+c+\" = the rate of the current
\n" ); document.write( "Let \"+t+\" = time in hrs for both trips
\n" ); document.write( "------------------
\n" ); document.write( "Equation for going upstream:
\n" ); document.write( "(1) \"+10+=+%28+9+-+c+%29%2At+\"
\n" ); document.write( "Equation for going downstream:
\n" ); document.write( "(2) \"+20+=+%28+9+%2B+c+%29%2At+\"
\n" ); document.write( "------------------------------
\n" ); document.write( "(1) \"+t+=+10%2F%28+9+-+c+%29+\"
\n" ); document.write( "Plug (1) into (2)
\n" ); document.write( "(2) \"+20+=+%28+9+%2B+c+%29%2A%28+10%2F%28+9+-+c+%29+%29+\"
\n" ); document.write( "(2) \"+20%2A%28+9+-+c+%29+=+10%2A%28+9+%2B+c+%29+\"
\n" ); document.write( "(2) \"+180+-+20c+=+90+%2B+10c+\"
\n" ); document.write( "(2) \"+30c+=+90+\"
\n" ); document.write( "92) \"+c+=+3+\"
\n" ); document.write( "The rate of the current is 3 mi/hr
\n" ); document.write( "------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+10+=+%28+9+-+c+%29%2At+\"
\n" ); document.write( "(1) \"+10+=+%28+9+-+3+%29%2At+\"
\n" ); document.write( "(1) \"+10+=+6t+\"
\n" ); document.write( "(1) \"+t+=+5%2F3+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+20+=+%28+9+%2B+c+%29%2At+\"
\n" ); document.write( "(2) \"+20+=+%28+9+%2B+3+%29%2At+\"
\n" ); document.write( "(2) \"+20+=+12t+\"
\n" ); document.write( "(2) \"+t+=+5%2F3+\"
\n" ); document.write( "OK
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