document.write( "Question 1047143: Sarah Meehan blends coffee for taste-delight. She needs to prepare 160 pounds of coffee beans selling for $5.19 per pound. She plans to do this by blending together a high-quality bean costing $6.50 per pound and a cheaper bean at $3.50 per pound. To the nearest pound find how much high quality coffee bean and how much cheaper coffee bean she should blend. \n" ); document.write( "
Algebra.Com's Answer #662670 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Sarah Meehan blends coffee for taste-delight. She needs to prepare 160 pounds of coffee beans selling for $5.19 per pound. She plans to do this by blending together a high-quality bean costing $6.50 per pound and a cheaper bean at $3.50 per pound. To the nearest pound find how much high quality coffee bean and how much cheaper coffee bean she should blend. \n" ); document.write( "-------------------------- \n" ); document.write( "Using 2 variables:: \n" ); document.write( "H + L = 160 lbs \n" ); document.write( "6.5H + 3.5L = 5.19*160 \n" ); document.write( "--------------------------------- \n" ); document.write( "65H + 65L = 65*160 \n" ); document.write( "65H + 35L = 51.9*160 \n" ); document.write( "--------------------------- \n" ); document.write( "Substract and solve for \"L\":: \n" ); document.write( "30L = 13.1*160 \n" ); document.write( "L = 69.87 lbs (amt. of lower priced coffee) \n" ); document.write( "H = 160-69.87 = 90.13 lbs (amt. of higher priced coffee) \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |