document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047149>Question 1047149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circular fish pond with a diameter of 4 m, has circular paving that is 1,2 m wide around it. The litres<BR>\n" );
document.write( "of paving paint that will have to be bought to cover the paving if 2 litres are needed per square metre,<BR>\n" );
document.write( "rounded to the nearest litre, is . . . .<BR>\n" );
document.write( "[1] 39 &#8467;<BR>\n" );
document.write( "[2] 40 &#8467;<BR>\n" );
document.write( "[3] 20 &#8467;<BR>\n" );
document.write( "[4] 69 &#8467; </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662656 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The whole pond and paving has diameter 6.4 meters , 4 for the pond and 1.2 m on each side.<BR>\n" );
document.write( "The area of the whole circle with radius 3.2 meters, half of 6.4, is pi*(3.2^2)=32.17 m^2.<BR>\n" );
document.write( "The area of the pond with radius 2 meters, half of 4, is 4pi=12.57 m^2.C<BR>\n" );
document.write( "Therefore, the area of pavement is the difference, or 19.60 m^2<BR>\n" );
document.write( "If there is 2 liters of pavement/m^2, then the paint needed would be 39.2 or 39 liters to the nearest l.<BR>\n" );
document.write( "Choice [1]. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );