document.write( "Question 1047107: Ten candidates apply for a job and are separately interviewed. Based on past experience, any candidate has a 65% chance of passing to a second interview. What is the probability that: [17]
\n" ); document.write( "At least eight candidates pass to a second interview
\n" ); document.write( "More than two but less than six candidates pass to a second interview
\n" ); document.write( "At most three candidates do not pass to a second interview
\n" ); document.write( "If 540 candidates applied for the job and were interviewed, what is the variance and the expected number of candidates that will pass to a second interview?
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Algebra.Com's Answer #662622 by Timnewman(323) $\"\"$ $\"About$

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xy=14
\n" ); document.write( " x+y=9
\n" ); document.write( "solution
\n" ); document.write( "xy=14---(1)
\n" ); document.write( "x+y=9---(2)
\n" ); document.write( "from equ 2,
\n" ); document.write( "y=9-x ---(3)
\n" ); document.write( "put 3 in 1,
\n" ); document.write( " x(9-x)=14
\n" ); document.write( "9x-x^2=14
\n" ); document.write( "x^2-9x+14=0
\n" ); document.write( "factorize the above,
\n" ); document.write( "(x-2)(x-7)=0
\n" ); document.write( "x=2 or x=7
\n" ); document.write( "put x=2 in equ 3
\n" ); document.write( "y=9-3
\n" ); document.write( "y=7.
\n" ); document.write( "The value for x and y is 2 and 7 . \n" ); document.write( "

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