document.write( "Question 1047115: The lines y = 3x - 25 and y = -3/4x + 17 intersect at point P. How far is P from the origin? \n" ); document.write( "
Algebra.Com's Answer #662619 by MathLover1(20850)\"\" \"About 
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\"y+=+3x+-+25\".......eq.1
\n" ); document.write( "\"y+=+-%283%2F4%29x+%2B+17\".......eq.2
\n" ); document.write( "-----------------------------------since left sides equal, we have
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\n" ); document.write( "\"3x+-+25=-%283%2F4%29x+%2B+17\"......solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B%283x%2F4%29=25+%2B+17\"\r
\n" ); document.write( "\n" ); document.write( "\"%2812x+%2B3x%29%2F4=42\"\r
\n" ); document.write( "\n" ); document.write( "\"15x=42%2A4\"\r
\n" ); document.write( "\n" ); document.write( "\"15x=168\"\r
\n" ); document.write( "\n" ); document.write( "\"x=168%2F15\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+56%2F5\"
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\n" ); document.write( "or approximately\r
\n" ); document.write( "\n" ); document.write( "\"x=11.2\"\r
\n" ); document.write( "\n" ); document.write( "find \"y\":\r
\n" ); document.write( "\n" ); document.write( "\"y+=+3x+-+25\".......eq.1 \r
\n" ); document.write( "\n" ); document.write( "\"y+=+3%2A%2856%2F5%29+-+25\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+168%2F5%29+-+125%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+43%2F5\"
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\n" ); document.write( "or approximately\r
\n" ); document.write( "\n" ); document.write( "\"y+=+8.6\" \r
\n" ); document.write( "\n" ); document.write( " so, the lines intersect at point P (\"56%2F5\",\"43%2F5\")\r
\n" ); document.write( "\n" ); document.write( " to find out how far is P from the origin (\"0\",\"0\"), use distance formula:\r
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Solved by pluggable solver: Distance Formula

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\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
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\n" ); document.write( " Since the first point is (0, 0), we can say (x1, y1) = (0, 0)
\n" ); document.write( " So \"x%5B1%5D+=+0\", \"y%5B1%5D+=+0\"
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\n" ); document.write( " Since the second point is (11.2, 8.6), we can also say (x2, y2) = (11.2, 8.6)
\n" ); document.write( " So \"x%5B2%5D+=+11.2\", \"y%5B2%5D+=+8.6\"
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\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+0\", \"y%5B1%5D+=+0\", \"x%5B2%5D+=+11.2\", and \"y%5B2%5D+=+8.6\"
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\n" ); document.write( " Now use the distance formula to find the distance between the two points (0, 0) and (11.2, 8.6)
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\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%28%280+-+11.2%29%5E2+%2B+%280+-+8.6%29%5E2%29\" Plug in \"x%5B1%5D+=+0\", \"y%5B1%5D+=+0\", \"x%5B2%5D+=+11.2\", and \"y%5B2%5D+=+8.6\"
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\n" ); document.write( " \"d+=+sqrt%28%28-11.2%29%5E2+%2B+%28-8.6%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%28125.44+%2B+73.96%29\"
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\n" ); document.write( " \"d+=+sqrt%28199.4%29\"
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\n" ); document.write( " \"d+=+14.1209064864831\"
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\n" ); document.write( " Answer:
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\n" ); document.write( " The distance between the two points (0, 0) and (11.2, 8.6) is exactly \"sqrt%28199.4%29\" units
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\n" ); document.write( " The approximate distance between the two points is about 14.1209064864831 units
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\n" ); document.write( " So again,
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\n" ); document.write( " Exact Distance: \"sqrt%28199.4%29\" units
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\n" ); document.write( " Approximate Distance: \"14.1209064864831\" units
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