document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047107>Question 1047107</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ten candidates apply for a job and are separately interviewed. Based on past experience, any candidate has a 65% chance of passing to a second interview. What is the probability that:	[17]<BR>\n" );
document.write( "At least eight candidates pass to a second interview<BR>\n" );
document.write( "More than two but less than six candidates pass to a second interview<BR>\n" );
document.write( "At most three candidates do not pass to a second interview<BR>\n" );
document.write( "If 540 candidates applied for the job and were interviewed, what is the variance and the expected number of candidates that will pass to a second interview?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662594 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Binomial distribution (EITHER MAKE IT THRU OR NOT)<BR>\n" );
document.write( "p(passing to 2nd Interview) = .65 and n = 10<BR>\n" );
document.write( " TI syntax is binomcdf(n, p, largest x-value) for binomial &#8804; cumulative probability<BR>\n" );
document.write( "P(x >= 8) = find P(x &#8805; 8) = 1 – P(x &#8804; 7) = 1 - binomcdf(20, .65, 7) = 1 - .006\r<BR>\n" );
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document.write( "P(2 < x < 6) = p( 3 <= X &#8804; 5) = binomcdf(20, .65, 5) - binomcdf(20, .65, 3) = .00030- .000006 \r<BR>\n" );
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document.write( "P (x <= 3) = binomcdf(20, .65, 3)  = .000006\r<BR>\n" );
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document.write( "If 540 candidates applied for the job and were interviewed:<BR>\n" );
document.write( "Binomial distribution<BR>\n" );
document.write( "mean = np = .65(540)		<BR>\n" );
document.write( "variance = npq= np(1-p) = .35(.65*540)		<BR>\n" );
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