document.write( "Question 1047093: any number of the form \"abcabc\" must be divisible by which of the following:
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document.write( "(1)8
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document.write( "(2)7,13,11
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document.write( "(3)9 \n" );
document.write( "
Algebra.Com's Answer #662574 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the answer is selection 2. \n" ); document.write( "it must be divisible by 7 and 13 and 11. \n" ); document.write( "i have no idea why.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it must be means there are no exceptions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i took 123123 and divided it by 8 and 9 and did not get integers, so it can't be 8 or 9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i took 123123 and divided it by 7 and got an integer. \n" ); document.write( "i then divided it by 13 and got an integer. \n" ); document.write( "i then divided it by 11 and got an integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i then took another random number and did the same.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i took 987987 \n" ); document.write( "same result. \n" ); document.write( "it was not divisible by 8 or 9. \n" ); document.write( "it was divisible by 7, 13, and 11.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i then took 7 * 13 * 11 and got 1001.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i then divided 123123 by 1001 and got 123\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i then divided 987987 by 1001 and got 987.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "interesting.........\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since 1001 is equal to 1000 + 1, i then looked at:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "123 * 1001 = 123 * (1000 + 1) = 123000 + 123 = 123123.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i then looked at:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "987 * 1001 = 987 * (1000 + 1) = 987000 + 987 = 987987.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since abc * 1001 is equal to abc * 1000 + abc * 1 which is equal to abcabc, then:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "abcabc / 1001 is equal to abc.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since 1001 is equal to (7 * 13 * 11), then:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "abc * 1001 is equal to abc * 7 * 13 * 11 which is then equal to abcabc.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "therefore abcabc / 1001 is equivalent to abcabc / (7 * 13 * 11).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since it's divisible by 1001, it has to be divisible by the factors of 1001, namely 7, 13, and 11.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's what i think is happening.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |