document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047033>Question 1047033</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2/3 of a number is less than the original number by 11. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662519 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the original number x.  Then we have<BR>\n" );
document.write( "x - (2/3)x = 11<BR>\n" );
document.write( "Simplifying and solving we get<BR>\n" );
document.write( "(1/3)x = 11<BR>\n" );
document.write( "x = 33 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );