document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047034>Question 1047034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> $20,000 is invested, part at 4% and remainder at 6%.  The total income is $1050 from the 2 investments.  Determine amt. at each rate.\r<BR>\n" );
document.write( "\n" );
document.write( "My attempt:\r<BR>\n" );
document.write( "\n" );
document.write( "Let x = amt. at 4%  (4% is .04)\r<BR>\n" );
document.write( "\n" );
document.write( "20,000 - x = amt. at 6% (6% is .06)\r<BR>\n" );
document.write( "\n" );
document.write( "Not sure from here. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662511 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That's fine as far as you have gone.<BR>\n" );
document.write( "make the two add to equal $1050.<BR>\n" );
document.write( ".04x+.06(20000-x)=$1050<BR>\n" );
document.write( ".04x+1200-.06x=1050<BR>\n" );
document.write( "-,02x=-150<BR>\n" );
document.write( "x=$7500 @4% ($300 a year)<BR>\n" );
document.write( "20000-x=$12500@6%=$750 a year.  They add to $1050 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );