document.write( "Question 1046976: You have 90 balls altogether. 20 of them are white, 25 are blue,
\n" ); document.write( "27 are red, and 18 are green. Now you will draw a ball one at a
\n" ); document.write( "time randomly until you've drawn any of the following: either 11
\n" ); document.write( "white, 9 blue, 3 red, or 14 green. What is the minimum number of
\n" ); document.write( "balls you have to draw until you are 100% sure that you've gotten
\n" ); document.write( "one of the previous combinations? \n" ); document.write( "

Algebra.Com's Answer #662492 by Edwin McCravy(20060) $\"\"$ $\"About$

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You have 90 balls altogether. 20 of them are white, 25 are blue,
\n" ); document.write( "27 are red, and 18 are green. Now you will draw a ball one at a
\n" ); document.write( "time randomly until you've drawn any of the following: either 11
\n" ); document.write( "white, 9 blue, 3 red, or 14 green. What is the minimum number of
\n" ); document.write( "balls you have to draw until you are 100% sure that you've gotten
\n" ); document.write( "one of the previous combinations?
\n" ); document.write( "

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document.write( "The most number of balls you could possibly have drawn and failed \r\n" );
document.write( "is to have drawn 10 whites, 8 blues, 2 reds and 13 greens. That\r\n" );
document.write( "case is possible when 10+8+2+13=33 balls are drawn.  You would \r\n" );
document.write( "necessarily have more than 10 whites or 8 blues or 2 reds or 13 \r\n" );
document.write( "greens in any other case of drawing 33 balls.  That is to say, \r\n" );
document.write( "any other case when 33 balls have been drawn will be a success.  \r\n" );
document.write( "But even in that extreme case, if you draw one more ball, you \r\n" );
document.write( "must succeed.\r\n" );
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document.write( "Answer: 34 balls.  \r\n" );
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document.write( "Edwin

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