document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1046990>Question 1046990</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to mix three different solutions to create 100 milliliters of a solution that is 24.5% alcohol.Solution A is 10% alcohol, solution B is 15% alcohol and solution C is 30% alcohol. The amount of solution A that is used must be twice the amount of solution B that is used.How many milliliters of each solution should the chemist combine?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662469 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662469\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let b=x<BR>\n" );
document.write( "then a=2x<BR>\n" );
document.write( "and c=100-3x<BR>\n" );
document.write( "That adds to 100 ml<BR>\n" );
document.write( "0.10(2x)+(0.15)(x)+(0.3)(100-3x)=100(0.245)<BR>\n" );
document.write( "0.2x+0.15x+30-0.9x=24.5<BR>\n" );
document.write( "-0.55x+30=24.5<BR>\n" );
document.write( "-0.55x=-5.5<BR>\n" );
document.write( "x=10 ml B<BR>\n" );
document.write( "2x=20 ml A<BR>\n" );
document.write( "100-3x=70 ml C<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );