document.write( "Question 1046897: The length of a rectangle is 8m more than twice the width . If the perimeter of the rectangle is 352m, find the dimensions \n" ); document.write( "

Algebra.Com's Answer #662375 by ikleyn(52782) $\"\"$ $\"About$

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\n" ); document.write( "The length of a rectangle is 8m more than twice the width. If the perimeter of the rectangle is 352m, find the dimensions
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document.write( "Let W be the the width, in meters.\r\n" );
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document.write( "Then the length is (2W+8), according to the condition.\r\n" );
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document.write( "For the perimeter you have this equation\r\n" );
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document.write( "W + (2W+8) + W + (2W+8) = 352,   or\r\n" );
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document.write( "6W + 16 = 352,   or\r\n" );
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document.write( "6W = 362 - 16,\r\n" );
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document.write( "6W = 336,\r\n" );
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document.write( "W =  = 56 m.\r\n" );
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document.write( "The length of a rectangle is 2W+8 = 2*56+8 = 120 m.\r\n" );
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document.write( "Answer. The dimensions of the rectangle are 56 m and 120 m.\r\n" );
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