document.write( "Question 1046875: What is the inverse equation for:
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document.write( "h(x)= (2x-1)/(x+1) \n" );
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Algebra.Com's Answer #662318 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! What is the inverse equation for: \n" ); document.write( "h(x)= (2x-1)/(x+1) \n" ); document.write( "--------------- \n" ); document.write( "1st: Interchange x and y to get: \n" ); document.write( "x = (2y-1)/(y+1) \n" ); document.write( "------ \n" ); document.write( "2nd: Solve for \"y\":: \n" ); document.write( "xy+x = 2y-1 \n" ); document.write( "---- \n" ); document.write( "xy-2y = -(x+1) \n" ); document.write( "y(x-2) = -(x+1) \n" ); document.write( "y = -(x+1)/(x-2) \n" ); document.write( "That is the inverse. \n" ); document.write( "-------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " |