document.write( "Question 1046875: What is the inverse equation for:
\n" ); document.write( "h(x)= (2x-1)/(x+1)
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Algebra.Com's Answer #662318 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
What is the inverse equation for:
\n" ); document.write( "h(x)= (2x-1)/(x+1)
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\n" ); document.write( "1st: Interchange x and y to get:
\n" ); document.write( "x = (2y-1)/(y+1)
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\n" ); document.write( "2nd: Solve for \"y\"::
\n" ); document.write( "xy+x = 2y-1
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\n" ); document.write( "xy-2y = -(x+1)
\n" ); document.write( "y(x-2) = -(x+1)
\n" ); document.write( "y = -(x+1)/(x-2)
\n" ); document.write( "That is the inverse.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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