document.write( "Question 1046845: Last year, Dan had
\n" ); document.write( "$30,000
\n" ); document.write( " to invest. He invested some of it in an account that paid
\n" ); document.write( "5%
\n" ); document.write( " simple interest per year, and he invested the rest in an account that paid
\n" ); document.write( "10%
\n" ); document.write( " simple interest per year. After one year, he received a total of
\n" ); document.write( "$1950
\n" ); document.write( " in interest. How much did he invest in each account?
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Algebra.Com's Answer #662289 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
Some at 5%, rest at 10%
\n" ); document.write( "Use .05 and .10 for the Arithmetic
\n" ); document.write( "Let x be the amount at 10%
\n" ); document.write( ".10x + .05(30000 - x) = 1950
\n" ); document.write( ".05x = 1950 - 1500
\n" ); document.write( "x = 450/.05
\n" ); document.write( "x = $9000, the amount at 10%. \"30000-9000\" = $21,000 at 5%
\n" ); document.write( "CHECK...
\n" ); document.write( "$900 + $1050 = $1950
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