document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1046814>Question 1046814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pure acid is to be added to a 10% acid solution to obtain 90L of 42% solution what amounts of each should be used?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662259 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1x+0.10(90-x) = 0.42(90)<BR>\n" );
document.write( "x+9-0.10x = 37.8<BR>\n" );
document.write( "0.9x = 28.8<BR>\n" );
document.write( "x = 32L of pure acid to 90-32 = 58L of 10% solution to get 90L at 42% </SPAN>\n" );
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