document.write( "Question 1046809: three consecutive even integers are such that if the second is added to twice the first the result is 18 more than the third. find these integers \n" ); document.write( "

Algebra.Com's Answer #662256 by josmiceli(19441) $\"\"$ $\"About$

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Let the consecutive even integers be:
\n" ); document.write( " $\"+n+\"$ , $\"+n%2B2++\"$ , and $\"+n+%2B+4+\"$
\n" ); document.write( "---------------------------------
\n" ); document.write( " $\"+n+%2B+2+%2B+2n+=+n+%2B+4+%2B+18+\"$
\n" ); document.write( " $\"+3n+%2B+2+=+n+%2B+22+\"$
\n" ); document.write( " $\"+2n+=+20+\"$
\n" ); document.write( " $\"+n+=+10+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+n+%2B+2+=+12+\"$
\n" ); document.write( " $\"+n+%2B+4+=+14+\"$
\n" ); document.write( "The consecutive even integers are:
\n" ); document.write( "10, 12, and 14
\n" ); document.write( "-------------------
\n" ); document.write( " $\"+n+%2B+2+%2B+2n+=+n+%2B+4+%2B+18+\"$
\n" ); document.write( " $\"+10+%2B+2+%2B+2%2A10+=+10+%2B+4+%2B+18+\"$
\n" ); document.write( " $\"+12+%2B+20+=+14+%2B+18+\"$
\n" ); document.write( " $\"+32+=+32+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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