document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1046794>Question 1046794</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An experiment calls for a 6% salt solution. Only a 3% salt solution and an 8% salt solution are available. How many gallons of each must be combined to obtain 40 gallons of a 6% salt solution?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662246 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount of 8% solution<BR>\n" );
document.write( "decimal used for this Arithmetic<BR>\n" );
document.write( "MIX<BR>\n" );
document.write( ".08x + .03(40gal - x) = .06(40gal)<BR>\n" );
document.write( ".05x = .03(40gal)<BR>\n" );
document.write( "x = .03(40)/.05) = 24gal , the amount of 8% solution<BR>\n" );
document.write( "16gal <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40-24 ALIGN=MIDDLE  ALT=\"40-24\"   DISABLED_style= \"max-width:90%; height:auto;\" > the amount of 3% solution </SPAN>\n" );
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