document.write( "Question 91061: Lauren wants to mix 5 liters of 7% milk with skim-milk (0% fat) to profud a mixture of 2 46/47% milk. How much skim-milk should Lauren add? \n" ); document.write( "

Algebra.Com's Answer #66224 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Lauren wants to mix 5 liters of 7% milk with skim-milk (0% fat) to produce a mixture of 2 46/47% milk. How much skim-milk should Lauren add?
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\n" ); document.write( "Let x = amt of skim milk to be added:
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\n" ); document.write( "Change 2 46/47 to a improper fraction: 2*47 + 46 = 140/47 %;
\n" ); document.write( "Change to decimal equiv: 140/47 divided by 100 = 140/4700 = 14/470 = 7/235
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\n" ); document.write( "The percent equation:
\n" ); document.write( ".07(5) + 0(x) = $\"7%2F235\"$ (x + 5)
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\n" ); document.write( ".35 + 0 = $\"7%2F235\"$ (x + 5)
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\n" ); document.write( "multiply equation by 235:
\n" ); document.write( "235(.35) = 7(x + 5)
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\n" ); document.write( "82.85 = 7x + 35
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\n" ); document.write( "7x = 82.85 - 35
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\n" ); document.write( "7x = 47.25
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\n" ); document.write( "x = 47.25/7
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\n" ); document.write( "x = 6.75 liters of skim milk
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\n" ); document.write( "Check:
\n" ); document.write( " $\"7%2F235\"$ (6.75 + 5) = .7(5)
\n" ); document.write( " $\"7%2F235\"$ (11.75) = .35\r
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