document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=598229>Question 598229</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are twenty-seven animals in a barn. Some are chickens some are cows. There are 90 legs in all. How many of each animal are in the barn? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #662189 by </B><A HREF=/tutors/aboutme.mpl?userid=chungchengg><B>chungchengg(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chungchengg><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=662189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let ch = number of chickens<BR>\n" );
document.write( "let co = number of cows\r<BR>\n" );
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document.write( "there are 27 animals so you can make an equation \r<BR>\n" );
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document.write( "ch + co = 27<BR>\n" );
document.write( "ch = 27 - co    equation # 1\r<BR>\n" );
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document.write( "since there are only 2 legs for chickens and 4 legs for cows and the total legs are 90 you can make another equation\r<BR>\n" );
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document.write( "2ch + 4co = 90 equation # 2........then substitute the equation #1 to equation # 2<BR>\n" );
document.write( " 2(27-co) + 4co =90<BR>\n" );
document.write( "54 + 4co = 90<BR>\n" );
document.write( "      co = 9\r<BR>\n" );
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document.write( "since co for cows are 9...and the total animals are 27 ....chickens will be 18 </SPAN>\n" );
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