document.write( "Question 1046678: Please help me with the solution for this question. A student interviewing at a major company wants to know his chances of getting a job offer. He surveyed 18 alumni that had interviewed with company and found9 of them had received a job offer. construct a 90% confidence interval for the population proportion? \n" ); document.write( "

Algebra.Com's Answer #662158 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
Please help me with the solution for this question. A student interviewing at a major company wants to know his chances of getting a job offer. He surveyed 18 alumni that had interviewed with company and found 9 of them had received a job offer. construct a 90% confidence interval for the population proportion?
\n" ); document.write( "-----
\n" ); document.write( "Sample proportion = p-hat = 9/18 = 0.5
\n" ); document.write( "----
\n" ); document.write( "Margin of Error = E = z*sqrt(pq/n) = 1.645*sqrt[0.5*0.5/18] = 0.1938
\n" ); document.write( "-----
\n" ); document.write( "90% CI:: (p-hat)-ME < p < (p-hat+ME)
\n" ); document.write( "----
\n" ); document.write( "90% CI: 0.5-0.1938 < p < 0.5+0.1938
\n" ); document.write( "-----
\n" ); document.write( "90% CI: 0.3062 < 0.6938
\n" ); document.write( "-----------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "------------- \n" ); document.write( "

\n" );