document.write( "Question 1046626: The width of a rectangle is four less than one half the length. If the perimeter of the rectangle is 94 m find the area of the rectangle \n" ); document.write( "
Algebra.Com's Answer #662065 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( " .
\n" ); document.write( "The width of a rectangle is four less than one half the length.
\n" ); document.write( "Let L represent the length and \"L%2F2+-+4\" the width\r
\n" ); document.write( "\n" ); document.write( "perimeter of the rectangle is 94 m
\n" ); document.write( "P = 2L + 2w
\n" ); document.write( "94m = 2L + 2(L/2 - 4)
\n" ); document.write( "94m = 2L + 2(L/2) - 8
\n" ); document.write( "102m = 3L
\n" ); document.write( "34m = L and width is 13m. \"L%2F2+-+4\", 68 + 26 = 94 CHECKS!\r
\n" ); document.write( "\n" ); document.write( "A = Lw
\n" ); document.write( "A = (34m)(13m) = 442m^2 (check with Your calculator) \n" ); document.write( "
\n" );