document.write( "Question 91211: Erin’s age is 3 times Warren’s. in 4 years she will be twice as old as he will be. How old is each? \n" ); document.write( "
Algebra.Com's Answer #66203 by Earlsdon(6294)\"\" \"About 
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Start by assigning variables the the unknown quantities.
\n" ); document.write( "Let E = Erin's present age.
\n" ); document.write( "Let W = Warren's present age.
\n" ); document.write( "Erin's age (E)is (=) three times Warren's (3W), so you can write:
\n" ); document.write( "1) E = 3W
\n" ); document.write( "In four years, Erin's age (E+4) will be (=) twice Warren's (2(W+4)), so you can write:
\n" ); document.write( "2) E+4 = 2(W+4) Substitute from equation 1) E = 3W and solve for W.
\n" ); document.write( "3W+4 = 2(W+4) Simplify.
\n" ); document.write( "3W+4 = 2W+8 Subtract 2W from both sides.
\n" ); document.write( "W+4 = 8 Subtract 4 from both sides.
\n" ); document.write( "W = 4 This is Warren's present age.
\n" ); document.write( "E = 3W
\n" ); document.write( "E = 3(4)
\n" ); document.write( "E = 12 This is Erin's present age.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "E+4 = 2(W+4)
\n" ); document.write( "12+4 = 2(4+4)
\n" ); document.write( "16 = 2(8)
\n" ); document.write( "16 = 16
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