document.write( "Question 1046271: If cos(A-B)+cos(B-C)+cos(C-A)= -3/2, prove that: cosA+cosB+cosC=sinA+sinB+sinC=0. \n" ); document.write( "
Algebra.Com's Answer #662021 by robertb(5830)![]() ![]() You can put this solution on YOUR website! Consider \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "But \n" ); document.write( "\n" ); document.write( "Since the values of A, B, and C are real, all the sine and cosine values are also real, and so, we conclude that \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cosA+cosB+cosC = 0 and sinA+sinB+sinC = 0. \n" ); document.write( " |