document.write( "Question 1046559: The function C(x)=119x+750 represents the cost of producing x three-pronged stainless steel widgets. R(x)=169x represents the revenue from selling x of them. Find the following.\r
\n" ); document.write( "\n" ); document.write( "a. number that must be sold to break even.
\n" ); document.write( "b. profit from selling 500.
\n" ); document.write( "c. profit or loss from selling 200 at the regular price and 300 at half price.
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Algebra.Com's Answer #662009 by josgarithmetic(39627)\"\" \"About 
You can put this solution on YOUR website!
Profit is revenue minus cost, or \"R%28x%29-C%28x%29=169x-119x-750=highlight_green%2850x-750%29\".\r
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\n" ); document.write( "\n" ); document.write( "For break-even, \"50x-750=0\".\r
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\n" ); document.write( "\n" ); document.write( "For profit of selling 500 items, \"50%2A500-750\".\r
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\n" ); document.write( "\n" ); document.write( "You want to find prices for solving the last question.
\n" ); document.write( "\"C%28x%29%2Fx\" is price. This would not be constant, so possibly the question should not really be answered this way. But continuing, price is \"119%2B750%2Fx\" for a \"regular\" price. \r
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\n" ); document.write( "\n" ); document.write( "HALF the regular price would be \"%281%2F2%29%28119%2B750%2Fx%29\".\r
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\n" ); document.write( "\n" ); document.write( "These should mean that 200 items will be given price of \"119%2B75%2F20\" per item, and that 300 items at half price will be given a price of \"%281%2F2%29%28119%2B75%2F30%29\" per item.\r
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\n" ); document.write( "\n" ); document.write( "None of that changes the revenue, still carrying the same formula \"R=169x\".\r
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\n" ); document.write( "\n" ); document.write( "You can continue working with the question c. if you want to.
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