document.write( "Question 1046550: the length of a rectangle is 1.75 cm longer than the width. The parameter is 17.5 cm. what is the length of the sides and area of the triangle \n" ); document.write( "
Algebra.Com's Answer #661986 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "I presume you mean that the perimeter is 17.5 cm. Yes, spelling is important. Yes, using the correct terminology is important. No, I don't \"know\" what you mean, I can only make plausible assumptions.\r
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\n" ); document.write( "\n" ); document.write( "Let represent the width of the rectangle. Then the length must be .\r
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is given by 2 times the length plus 2 time the width, so in this case:\r
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\n" ); document.write( "\n" ); document.write( "Solve the equation for , then calculate to determine the length.\r
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\n" ); document.write( "\n" ); document.write( "The area is given by the length times the width. Find the product of the two results above.\r
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\n" ); document.write( "\n" ); document.write( "Given correct arithmetic, you will arrive at an answer for the area that has 3 decimal places. It is an error to report the answer to this question with 3 decimal place precision since the least precise measurement provided in the stem of the problem is to 1 decimal place. The correct answers to both parts of this question should be rounded to the nearest one-tenth centimeter.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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