document.write( "Question 91212: A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current. (using the 5- step method ) \n" ); document.write( "
Algebra.Com's Answer #66196 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 20/3=S+C S=SPEED & C=CURRENT \n" ); document.write( "20/4=S-C NOW ADD THESE TWO EQUATIONS \n" ); document.write( "----------------------- \n" ); document.write( "20/3+20/4=2S \n" ); document.write( "(20*4+20*3)/12=2S \n" ); document.write( "(80+60)/12=2S \n" ); document.write( "140/12=2S \n" ); document.write( "2S=140/12 \n" ); document.write( "2S=11.6667 \n" ); document.write( "S=11.6667/2 \n" ); document.write( "S=5.833 ANSWER FOR THE SPED OF THE SAIL BOAT. \n" ); document.write( "20/4=5.8333-C \n" ); document.write( "5=5.8333-C \n" ); document.write( "C=5.8333-5 \n" ); document.write( "C=.8333 SPEED OF THE CURRENT. \n" ); document.write( "PROOF \n" ); document.write( "20/3=5.8333+.8333 \n" ); document.write( "6.6667=6.6667\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |