document.write( "Question 91212: A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current. (using the 5- step method ) \n" ); document.write( "
Algebra.Com's Answer #66196 by checkley71(8403)\"\" \"About 
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20/3=S+C S=SPEED & C=CURRENT
\n" ); document.write( "20/4=S-C NOW ADD THESE TWO EQUATIONS
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\n" ); document.write( "20/3+20/4=2S
\n" ); document.write( "(20*4+20*3)/12=2S
\n" ); document.write( "(80+60)/12=2S
\n" ); document.write( "140/12=2S
\n" ); document.write( "2S=140/12
\n" ); document.write( "2S=11.6667
\n" ); document.write( "S=11.6667/2
\n" ); document.write( "S=5.833 ANSWER FOR THE SPED OF THE SAIL BOAT.
\n" ); document.write( "20/4=5.8333-C
\n" ); document.write( "5=5.8333-C
\n" ); document.write( "C=5.8333-5
\n" ); document.write( "C=.8333 SPEED OF THE CURRENT.
\n" ); document.write( "PROOF
\n" ); document.write( "20/3=5.8333+.8333
\n" ); document.write( "6.6667=6.6667\r
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