document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1046485>Question 1046485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a person has $2.95 in nickels and quarters. If she has five more nickels than quarters, how many of each coin does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #661926 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=661926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do it like this:<BR>\n" );
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document.write( "a coin bank containing only dimes and quarters has 20 more dimes than quarters. the total value of the coins us $9. how many quarters and dimes are in the coin bank?<BR>\n" );
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document.write( "Without the \"20 more dimes\" there would be pairs of coins, each pair worth 35 cents, and a total of $7.<BR>\n" );
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document.write( "700/35 = 20 pairs<BR>\n" );
document.write( "--> 20 Q's and 40 dimes.<BR>\n" );
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document.write( "The \"hard way\":<BR>\n" );
document.write( "10d + 25q = 900<BR>\n" );
document.write( "d = q + 20<BR>\n" );
document.write( "10(q+20) + 25q = 900<BR>\n" );
document.write( "35q = 700<BR>\n" );
document.write( "q = 20<BR>\n" );
document.write( "d = 40 </SPAN>\n" );
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