document.write( "Question 91198: Prove that cube root of 7 is an IRRATIONAL number. \n" ); document.write( "
Algebra.Com's Answer #66191 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Prove that cube root of 7 is an IRRATIONAL number ? \n" ); document.write( "Assume that cube rt 7 is rational. \n" ); document.write( "Then (7)^(1/3) = a/b where a and b are integers and a/b is reduced to lowest terms. \n" ); document.write( "Then a=b[7^(1/3)] \n" ); document.write( "Since a is a multiple of b and a is an integer, b divides a. \n" ); document.write( "Since b divides a, a = nb and n is an integer. \n" ); document.write( "Therefore 7^(1/3) = a/b = nb/b, so a/b is not reduced to lowest terms. \n" ); document.write( "----------- \n" ); document.write( "What led to this contradiction? \n" ); document.write( "The assumption that 7^(1/3) was rational. \n" ); document.write( "The assumption must be wrong. \n" ); document.write( "Therefore 7^(1/3) if irrational. \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |