document.write( "Question 1046280: Prove the statement using the ε, δ definition of a limit.\r
\n" ); document.write( "\n" ); document.write( "lim x^2=0
\n" ); document.write( "x→0
\n" ); document.write( "Given ε > 0, we need δ > 0 such that if 0 < |x − 0| <  δ, then |x2 − 0| <  ε⇔ ____________ <  ε ⇔
\n" ); document.write( "|x| < _____________. Take δ = ____________.Then 0 < |x − 0| <  δ right double arrow implies
\n" ); document.write( " |x2 − 0| < ε. Thus,
\n" ); document.write( "lim
\n" ); document.write( "x→0 x^2 = 0 by the definition of a limit.
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Algebra.Com's Answer #661868 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
1st blank: \"abs%28x%5E2%29\", or \"abs%28x%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "2nd blank: \"sqrt%28epsilon%29\"\r
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\n" ); document.write( "\n" ); document.write( "3rd blank: \"sqrt%28epsilon%29\"
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