document.write( "Question 1046356: The measure of ∠A is 35° more than three times the measure of ∠B. The sum of their measures is 135°. Find
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Algebra.Com's Answer #661829 by MathLover1(20850)\"\" \"About 
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The measure of ∠\"A\" is \"35\"° more than \"three\"\"+times\" the measure of ∠\"B\". The sum of their measures is \"135\"°.\r
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\n" ); document.write( "\n" ); document.write( "if \"A%2BB=135\"° we have\r
\n" ); document.write( "\n" ); document.write( "\"%283B%2B35%29%2BB=135\"°\r
\n" ); document.write( "\n" ); document.write( "\"4B%2B35=135\"°\r
\n" ); document.write( "\n" ); document.write( "\"4B=135-35\"°\r
\n" ); document.write( "\n" ); document.write( "\"4B=100\"°\r
\n" ); document.write( "\n" ); document.write( "\"B=100%2F4\"°\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28B=25%29\"°\r
\n" ); document.write( "\n" ); document.write( "now find \"A\"\r
\n" ); document.write( "\n" ); document.write( "\"A=3B%2B35\"° ->\"A=3%2A25%2B35%29\"° ->\"A=75%2B35\"° ->\"highlight%28A=110%29\"° \r
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