document.write( "Question 1046347: find three consecutive odd integers that sum of two times the first, three times the second, and one times the third is -428 \n" ); document.write( "
Algebra.Com's Answer #661818 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let \"x\",\"%28x%2B2%29\",\"%28x%2B4%29\" represent the three consecutive odd integers \r
\n" ); document.write( "\n" ); document.write( "two times the first is \"2x\"\r
\n" ); document.write( "\n" ); document.write( "three times the second is \"3%28x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "if two times the first, three times the second, and one times the third is \"-428\", we have\r
\n" ); document.write( "\n" ); document.write( " \"2x%2B3%28x%2B2%29%2B%28x%2B4%29=+-428\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B3x%2B6%2Bx%2B4=-428\"\r
\n" ); document.write( "\n" ); document.write( "\"6x%2B10=-428\"\r
\n" ); document.write( "\n" ); document.write( "\"6x=-428-10\"\r
\n" ); document.write( "\n" ); document.write( "\"6x=-438\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-438%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-73\"-> first odd integer\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29\"->\"%28-73%2B2%29\"->\"-71\"->second odd integer\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29\"->\"%28-73%2B4%29\"->\"-69\"->third odd integer\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "check their sum:
\n" ); document.write( " two times the first is \"2%28-73%29=-146\"
\n" ); document.write( "three times the second is \"3%28-71%29=-213\"
\n" ); document.write( "and third one is \"-69\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-146%29%2B%28-213%29%2B%28-69%29=-428\"\r
\n" ); document.write( "\n" ); document.write( "\"-428=-428\"
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