document.write( "Question 1046353: The length of a rectangle is 2 cm less than twice the width. Express as an integer the maximum width of the rectangle when the perimeter is less than 66 cm. \n" ); document.write( "
Algebra.Com's Answer #661812 by jim_thompson5910(35256)\"\" \"About 
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L = length
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\n" ); document.write( "\n" ); document.write( "\"The length of a rectangle is 2 cm less than twice the width\" means that \"L+=+2W-2\"\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of rectangle = 2*(Length+Width)\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+2%2A%28L%2BW%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+2%2A%282W-2%2BW%29\" Replace L with 2W-2\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+2%2A%283W-2%29\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+6W-4\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+6W-4\"\r
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\n" ); document.write( "\n" ); document.write( "We are told that the \"perimeter is less than 66 cm\", so the perimeter P is smaller than 66 meaning that \"P+%3C+66\"\r
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\n" ); document.write( "\n" ); document.write( "\"P+%3C+66\" Start with the inequality\r
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\n" ); document.write( "\n" ); document.write( "\"6W-4+%3C+66\" Replace P with 6W-4. Solve for W\r
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\n" ); document.write( "\n" ); document.write( "\"6W-4%2B4+%3C+66%2B4\" Add 4 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"6W+%3C+70\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"6W%2F6+%3C+70%2F6\" Divide both sides by 6\r
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\n" ); document.write( "\n" ); document.write( "\"W+%3C+11.6666666666667\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "Since W is less than \"11.6666666666667\", this means that the largest W can be is \"W+=+11\"\r
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\n" ); document.write( "\n" ); document.write( "The maximum width is 11 cm
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