document.write( "Question 90936: Winter wheat. While finding the amount of seed needed to plant his three square wheat fields. Hank observed that the side of one field was 1 kilometer longer than the side of the smallest field and that the side of the largest field was 3 kilometers longer than the side of the smallest field. If the total area of the three fields is 38 square kilometers, then what is the area of each field? \n" ); document.write( "
Algebra.Com's Answer #66178 by ankor@dixie-net.com(22740)\"\" \"About 
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the side of one field was 1 kilometer longer than the side of the smallest field and that the side of the largest field was 3 kilometers longer than the side of the smallest field. If the total area of the three fields is 38 square kilometers, then what is the area of each field?
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\n" ); document.write( "Let x = side of the smallest
\n" ); document.write( "Then
\n" ); document.write( "(x+1) = side of the medium field
\n" ); document.write( "Then
\n" ); document.write( "(x+3) = side of the largest
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\n" ); document.write( "x^2 + (x+1)^2 + (x+3)^2 = 38
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\n" ); document.write( "x^2 + (x^2 + 2x + 1) + (x^2 + 6x + 9) = 38
\n" ); document.write( ":
\n" ); document.write( "x^2 + x^2 + x^2 + 2x + 6x + 1 + 9 - 38 = 0
\n" ); document.write( ":
\n" ); document.write( "3x^2 + 8x - 28 = 0
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\n" ); document.write( "(3x + 14)(x - 2) = 0
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\n" ); document.write( "x = +2 km is the side of the smallest field
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\n" ); document.write( "2^2 = 4 sq/km area of the smaller field
\n" ); document.write( ":
\n" ); document.write( "3^2 = 9 sq/km area of the medium field
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\n" ); document.write( "5^2 = 25 sq/km area of the largest field
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\n" ); document.write( "Check: 4 + 9 + 25 = 38 \n" ); document.write( "
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