document.write( "Question 1046314: The cost function for a certain company is C = 60x + 300 and the revenue is given by R = 100x - 0.5x^2 . Recall that profit is revenue minus cost. Set up a quadratic equation and find two values of x (production level) that will create a profit of $300. \n" ); document.write( "
Algebra.Com's Answer #661774 by josgarithmetic(39627)\"\" \"About 
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\"300=R-C\"\r
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\n" ); document.write( "\n" ); document.write( "\"100x-0.5x%5E2-60x-300=300\"\r
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\n" ); document.write( "\n" ); document.write( "\"40x-0.5x%5E2-600=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.5x%5E2-40x%2B600=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-80x%2B1200=0\"
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\n" ); document.write( "\n" ); document.write( "discriminant, \"%28-80%29%5E2-4%2A1200=6400-4800=1600=40%5E2\";\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28x=%2880%2B-+40%29%2F2%29\"
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