document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91113>Question 91113</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are three consecutive integers such that the sum of the first and second integers decreased by the third integer will result in 68.  What are the integers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66174 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X, X+1 & X+2 BE THE 3 NUMBERS.<BR>\n" );
document.write( "X+(X+1)-(X+2)=68<BR>\n" );
document.write( "X+X+1-X-2=68<BR>\n" );
document.write( "X-1=68<BR>\n" );
document.write( "X=68+1<BR>\n" );
document.write( "X=69 ANSWER FOR THE FIRST NUMBER<BR>\n" );
document.write( "X+1=70<BR>\n" );
document.write( "X+2=71<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "69+70-71=68<BR>\n" );
document.write( "139-71=68<BR>\n" );
document.write( "68=68<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );