document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91152>Question 91152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the formula for solving this problem<BR>\n" );
document.write( "Solve the equation two ways: by equating bases and using the uniqueness properties, and by applying a base-10 or base-e Logarithm and using the power property of Logarithms.<BR>\n" );
document.write( "243/64=16(3/4)^n-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66173 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 243/64 = 16(3/4)^n-1<BR>\n" );
document.write( "Divide both sides by 16 to get:<BR>\n" );
document.write( "(3/4)^(n-1) = 243/[64*16]<BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "(n-1)log(3/4) = log243-[log64+log16]<BR>\n" );
document.write( "(n-1)log(3/4) = -0.624693683...<BR>\n" );
document.write( "Divide both sides by log(3/4) to get:<BR>\n" );
document.write( "n-1 = 5<BR>\n" );
document.write( "n = 6<BR>\n" );
document.write( "==========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );